const numbers = [1, 2, 3, 4, 5];
const result = numbers
.filter(num => num % 2 === 0)
.map(num => num * num)
.reduce((acc, num) => acc + num, 0);
console.log(result);
Ответ:
20
JavaScript test | #JavaScript
JA JavaScript test @js_test · 9.72K subscribers
const numbers = [1, 2, 3, 4, 5];
const result = numbers
.filter(num => num % 2 === 0)
.map(num => num * num)
.reduce((acc, num) => acc + num, 0);
console.log(result);