function trickyArgs(a, b, c) {
arguments[0] = 10;
arguments[1] = 20;
arguments[2] = 30;
console.log(a + b + c);
}
trickyArgs(1, 2, 3);
Ответ:
60
JavaScript test | #JavaScript & Max
JA JavaScript test @js_test · 9.73K subscribers
function trickyArgs(a, b, c) {
arguments[0] = 10;
arguments[1] = 20;
arguments[2] = 30;
console.log(a + b + c);
}
trickyArgs(1, 2, 3);