Post #616
450
Словарь тестировщика | Тестирование SELECT user_id, COUNT(*) AS errors FROM logs WHERE level = 'ERROR' AND ts >= NOW() - INTERVAL '3 DAY' GROUP BY user_id HAVING COUNT(*) > ( SELECT AVG(cnt) FROM ( SELECT user_id, COUNT(*) AS cnt FROM logs WHERE level = 'ERROR' GROUP BY…
- 👍 2
- ✍ 1