Python Tasks & ML | Задачи по питону и машинному обучению

x = 1
def f1():
    return x
def f2():
    global x
    x = 2
    return x
def f3():
    global x
    return x
print(f1(), f2(), f3(), f1())

try:
    my_x = 1
    raise Exception('исключение') #1
except Exception as my_err:
    print(my_err)                 #2
    my_y = 2
print(my_x)                       #3
print(my_y)                       #4
print(my_err)                     #5

def f():
    x = 1
    y = 1
    def g():
        nonlocal x
        x, y = 2, 2
    g()
    print(x, y)

f()

def f(n):
    return 0 if n == 0 else 2**n + f(n-1)
print(f(3))

def intersect(*seqs):
    if len(seqs) > 2:
        return intersect(seqs[0], intersect(*seqs[1:]))
    seq1, seq2 = seqs[0], seqs[1]
    res = []
    for x in seq1:
        if x in seq2:
            res.append(x)    
    return res

x = intersect([1, 2, "a", "b"], (1, 4, "b"), {1, "b", "c"}) 
print(x)

class A:
    __x = 1
    def f(self):
        return "f from A"
    
    def g(self):
        return "g from A"

class B:
    __x = 2
    def f(self):
        return "f from B"
    
    def g(self):
        return "g from B"

class C(A, B):
    f = B.f
    
c = C()
print(c.f(), c.g(), c._A__x, c._B__x)

class MyList(list):
    def __getitem__(self, index):
        if type(index) is slice:
            index = slice(index.start - 1, index.stop - 1, index.step)
        elif type(index) is int:
            index -= 1
        return list.__getitem__(self, index)

l = MyList(["one", "two", "three", "four", "five", "six"])

print(l[1], l[-1], l[0], l[2:4])

a = 1 * 1
b = 1 / 1
print(a == 1, b == 1, a is 1, b is 1)

class A:
    def __init__(self, x):
        self.x = x
    def __getattribute__(self, name):
        if name == '__add__':
            self.x *= 10
        return object.__getattribute__(self, name)
    def __add__(self, other):
        return self.x + other.x

a1 = A(2)
a2 = A(3) 
print(a1 + a2, a1.__add__(a2))

class A:
    def __getitem__(self, i):
        return i
a = A()
a.__getitem__ = lambda i: i**2

print(a[4])