Что выведет код?

def intersect(*seqs):
    if len(seqs) > 2:
        return intersect(seqs[0], intersect(*seqs[1:]))
    seq1, seq2 = seqs[0], seqs[1]
    res = []
    for x in seq1:
        if x in seq2:
            res.append(x)    
    return res

x = intersect([1, 2, "a", "b"], (1, 4, "b"), {1, "b", "c"}) 
print(x)