Post #1051
346
π β π΄ππ«π± πΆπ¬π²π― π΄ππ―πͺπ±π₯, πΆπ¬π²π― π©π¬π³π’, ππ«π‘ π±π¬ π₯ππ³π’ π°π’π΅ π΄π¦π±π₯ πΆπ¬π². ππ©π© π¬π£ πΆπ¬π². ππ¬π² π₯ππ³π’ π«π¬ π¦π‘π’π π₯π¬π΄ πͺπ²π π₯.
- β€ 1
- π 1