const arr = [1, 2, 3, 4, 5];
const result = arr
.map(x => x * 2)
.filter(x => x > 5)
.reduce((acc, val) => {
return acc + (val % 3 === 0 ? val : 0);
}, 0);
console.log(result);
Ответ: 6
JavaScript test | #JavaScript & Max
JA JavaScript test @js_test · 9.76K subscribers
const arr = [1, 2, 3, 4, 5];
const result = arr
.map(x => x * 2)
.filter(x => x > 5)
.reduce((acc, val) => {
return acc + (val % 3 === 0 ? val : 0);
}, 0);
console.log(result);