const numbers = [1, 2, 3, 4, 5];
const result = numbers
.map(n => n * 2)
.filter(n => n > 5)
.reduce((acc, n, index) => {
acc.sum += n;
acc.indices.push(index);
return acc;
}, { sum: 0, indices: [] });
console.log(result.sum);
console.log(result.indices);
Ответ: 18 [0, 1, 2]
JavaScript test | #JavaScript & Max