const numbers = [1, 2, 3, 4, 5];
const result = numbers
.filter(n => n % 2 === 0)
.map(n => n * 2)
.reduce((acc, n) => acc + n, 0);
const original = numbers.slice();
original.reverse();
const flattened = [[1, 2], [3], [4, 5]].flat();
const found = flattened.find(n => n > 3);
console.log(result);
console.log(original.length);
console.log(found);
Ответ: [12, 16, 4, 8]
JavaScript test | #JavaScript & Max