function* gen() {
yield 1;
yield 2;
yield 3;
}
async function asyncFunc() {
for (let value of gen()) {
await new Promise(res => setTimeout(res, 100));
console.log(value);
}
return 'done';
}
const result = asyncFunc();
console.log(result instanceof Promise);
Ответ: true 1 2 3
JavaScript test | #JavaScript & Max