const numbers = [1, 2, 3, 4, 5];
const result = numbers
  .filter(n => n % 2 === 0)
  .map(n => n * 2)
  .reduce((acc, n) => acc + n, 0);

const original = numbers.slice();
original.reverse();

const flattened = [[1, 2], [3], [4, 5]].flat();
const found = flattened.find(n => n > 3);

console.log(result);
console.log(original.length);
console.log(found);