const arr = [1, 2, 3, 4, 5];
const result = arr
.map(x => x * 2)
.filter(x => x > 5)
.reduce((acc, val) => {
return acc + (val % 3 === 0 ? val : 0);
}, 0);
console.log(result);
Post #2112
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CHALLENGE
- 👍 12