🚨 SQL Interview Challenge (Most Candidates Get This Wrong!)

Ques:

Can you write a query to find employees who earn more than the average salary of their own department?

👀 Sounds simple… but this is where many people slip.

Ans:

SELECT e.*
FROM employees e
JOIN (
SELECT department_id, AVG(salary) AS avg_salary
FROM employees
GROUP BY department_id
) d
ON e.department_id = d.department_id
WHERE e.salary > d.avg_salary;

📌 Why interviewers love this:

It tests your understanding of correlated logic, aggregation, and joins.

💡 Key insight:

The comparison is done within each department, not across the entire table.

👍 If this clarified a tricky concept, react with 👍🔥

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