#challenge

💻 Oddish vs. Evenish | #easy

Create a function that determines whether a number is Oddish or Evenish. A number is Oddish if the sum of all of its digits is odd, and a number is Evenish if the sum of all of its digits is even. If a number is Oddish, return "Oddish". Otherwise, return "Evenish".

For example, OddishOrEvenish(121) should return "Evenish", since 1 + 2 + 1 = 4. OddishOrEvenish(41) should return "Oddish", since 4 + 1 = 5.

Examples:

OddishOrEvenish(43) ➞ "Oddish"
// 4 + 3 = 7
// 7 % 2 = 1

OddishOrEvenish(373) ➞ "Oddish"
// 3 + 7 + 3 = 13
// 13 % 2 = 1

OddishOrEvenish(4433) ➞ "Evenish"
// 4 + 4 + 3 + 3 = 14
// 14 % 2 = 0

🏆 Leave your solutions in the comments. The solution will be posted below in a couple of hours 👇

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